x^2+0,0450x-0,0007=0

Solution for x^2+0,0450x-0,0007=0 equation:

x^2+0.0450x-0.0007=0

a = 1; b = 0.0450; c = -0.0007;
Δ = b2-4ac
Δ = 0.04502-4·1·(-0.0007)
Δ = 0.004825
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.0450)-\sqrt{0.004825}}{2*1}=\frac{-0.045-\sqrt{0.004825}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.0450)+\sqrt{0.004825}}{2*1}=\frac{-0.045+\sqrt{0.004825}}{2}
$